A solution has a mass of #498*g#, and a volume of #1.2*L#. What is its density in units of #g*mL^-1#?

1 Answer
Feb 22, 2017

Answer:

#rho,# #"density"# #=# #"Mass"/"Volume"#

Explanation:

In your example, #rho=("Mass")/("Volume")=(598*g)/(1.2*cancelLxx10^(3)*mL*cancel(L^-1))# #=# #0.498*g*mL^-1#.

Is the solution likely to be aqueous? Why or why not?