# A solution has a mass of 498*g, and a volume of 1.2*L. What is its density in units of g*mL^-1?

##### 1 Answer
Feb 22, 2017

$\rho ,$ $\text{density}$ $=$ $\text{Mass"/"Volume}$

#### Explanation:

In your example, $\rho = \left(\text{Mass")/("Volume}\right) = \frac{598 \cdot g}{1.2 \cdot \cancel{L} \times {10}^{3} \cdot m L \cdot \cancel{{L}^{-} 1}}$ $=$ $0.498 \cdot g \cdot m {L}^{-} 1$.

Is the solution likely to be aqueous? Why or why not?