A solution has a mass of #498g#, and a volume of #1.2L#. What is its density in units of #g*mL^-1#?

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Answer 1 · 2017-02-22T18:42:21

#rho,# #"density"# #=# #"Mass"/"Volume"#

In your example, #rho=("Mass")/("Volume")=(598*g)/(1.2*cancelLxx10^(3)*mL*cancel(L^-1))# #=# #0.498*g*mL^-1#.

Is the solution likely to be aqueous? Why or why not?

A solution has a mass of #498*g#, and a volume of #1.2*L#. What is its density in units of #g*mL^-1#?