# What are the elemental oxidation states in nitrate anion, NO_3^(-)?

Feb 24, 2017

The nitrogen centre is formally ${N}^{+ V}$ in the $\text{nitrate anion.....}$ And as is typical, we gots $3 \times O \left(- I I\right)$..

#### Explanation:

The sum of the oxidation states of the individual elements in a compound ion ALWAYS equals the overall charge on the ion. Here we have the $N {O}_{3}^{-}$ ion, in which oxygen assumes its usual oxidation state of $- I I$. And thus

$3 \times \left(- I I\right) + {N}_{\text{oxidation state}} = - 1$

Add $+ 6$ to both sides:

${N}_{\text{oxidation state}} = + V$