# Under standard conditions, what volume does a 25*g mass of ammonia gas occupy?

Feb 28, 2017

Approx. $55 \cdot L$

#### Explanation:

$\text{Moles of ammonia } = \frac{25.0 \cdot g}{17.01 \cdot g \cdot m o {l}^{-} 1} = 1.47 \cdot m o l$.

Given the stoichiometry of the equation, I need $\frac{3}{2}$ equiv dihydrogen gas, i.e. $2.20 \cdot m o l$.

I don't know what your syllabus says in regard to the molar volume of an ideal gas at STP; the standard molar volume is $24.8 \cdot L \cdot m o {l}^{-} 1$, so we get:

2.20*molxx24.8*L*mol^-1=??L