# What mass of caustic soda are required to prepare a solution of 100*mL volume that is 1.0*mol*L^-1 with respect to NaOH?

Feb 27, 2017

A mass of $4.0 \cdot g$ $\text{sodium hydroxide}$ is required............

#### Explanation:

$\text{Concentration}$ $=$ $\text{Moles of solute"/"Volume of solution}$

Here, $\text{concentration}$ $=$ $1.0 \cdot m o l \cdot {L}^{-} 1$, $\text{volume}$ $=$ $100 \cdot m L$.

And thus $\text{moles of solute}$ $=$ $\text{Concentration "xx" Volume}$

$= 1 \cdot m o l \cdot {L}^{-} 1 \times 100 \times {10}^{-} 3 L = 0.100 \cdot m o l$.

And thus $\text{mass of solute}$ $=$ $\text{number of moles "xx" molar mass}$

=0.100*molxx40.0*g*mol^-1=??*g.