Question

Question #eb29e

Answer 1

`1.87*10^23` formula units of `Ba(NO_3)_2`

Explanation:

First compute the molar mass of `Ba(NO_3)_2`:

MM `= 137.3g+(2*14.007g)+(6*15.999g)=261.3(gBa(NO_3)_2)/(mol)`

Next use dimensional analysis to calculate the answer. Be sure to set up the units correctly and use appropriate conversions. Usually if you set up the units correctly, you'll get the correct answer.

`(81.3cancel(gBa(NO_3)_2))((1cancel(molBa(NO_3)_2))/(261.3cancel(gBa(NO_3)_2)))((6.02*10^23FU)/(1cancel(molBa(NO_3)_2)))=1.87*10^23FU`