Question #91fad
1 Answer
Mar 1, 2017
Explanation:
When dealing with
#color(blue)"inverse proportion"# we know that the relationship involves#color(blue)(1/("quantity"))#
#"the square of x means "x^2#
#rArryprop1/(x^2)# To convert into an equation, we require to introduce k ,
#color(blue)"the constant of proportion"#
#rArry=kxx1/x^2#
#rArry=k/x^2to(1)# To find k, use the given values of x and y.
#"That is "y=7.5" when "x=2.6#
#"From "(1):k=yx^2larr" cross-multiplying"#
#rArrk=7.5xx(2.6)^2=50.7#
#"We can now express "(1)" as "y=50.7/x^2#
#x=4.2toy=50.7/(4.2)^2#
#rArry=2.9" to 1 decimal place"#