If sinx=1/4sinx=14 and tanxtanx is positive, find cosxcosx? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Shwetank Mauria Mar 1, 2017 cosx=sqrt15/4cosx=√154 Explanation: As sinxsinx and tanxtanx both are positive, xx lies in Quadrant 1 and cosx=sinx/tanxcosx=sinxtanx too is positive. Hence, cosx=sqrt(1-sin^2x)=sqrt(1-(1/4)^2)=-sqrt(1-1/16)=-sqrt(15/16)=sqrt15/4cosx=√1−sin2x=√1−(14)2=−√1−116=−√1516=√154 Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If sec theta = 4secθ=4, how do you use the reciprocal identity to find cos thetacosθ? How do you find the domain and range of sine, cosine, and tangent? What quadrant does cot 325^@cot325∘ lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that 1+tan^2 theta = sec ^2 theta1+tan2θ=sec2θ? See all questions in Relating Trigonometric Functions Impact of this question 5250 views around the world You can reuse this answer Creative Commons License