# Question 33f42

Mar 2, 2017

The substance that has the higher density.

#### Explanation:

The density of a substance tells you the mass of exactly one unit of volume of said substance.

This implies that a substance with a higher density will have more mass concentrated in one unit of volume than a substance with a lower density.

In this case, water is said to have a density of ${\text{1.00 g mL}}^{- 1}$. This tells you that one unit of volume of water, i.e. in $\text{1 mL}$ of water, has a mass of $\text{1.00 g}$.

Gasoline is said to have a density of ${\text{0.68 g mL}}^{- 1}$. This tells you that one unit of volume of gasoline, i.e. $\text{1 mL}$ of gasoline, has a mass of $\text{0.68 g}$.

Consequently, you can say that because one unit of volume of water has a greater mass than one unit of volume of gasoline, any volume of water will have a greater mass than the same volume of gasoline.

In other words, when dealing with equal volumes of water and of gasoline, the sample of water will always have the greater mass.

So if

$\textcolor{b l u e}{\underline{\textcolor{b l a c k}{\text{1 L" = 10^3"mL}}}}$

you can say that

1 color(red)(cancel(color(black)("L water"))) * (10^3color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1.00 g"/(1color(red)(cancel(color(black)("mL water")))) = "1000 g"

and

1 color(red)(cancel(color(black)("L gasoline"))) * (10^3color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "0.68 g"/(1color(red)(cancel(color(black)("mL gasoline")))) = "680 g"#

As you can see, the sample of water has a greater mass than the sample of gasoline.