Simplify #5lnx +21lnx^3-3lnx^3+lnx^(1/2)#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Shwetank Mauria Mar 3, 2017 #5lnx +21lnx^3-3lnx^3+lnx^(1/2)=119/2lnx# Explanation: We can use the identities #lna+lnb-lnc=ln((ab)/c)# and #lna^b=blna#. Hence, #5lnx +21lnx^3-3lnx^3+lnx^(1/2)# = #5lnx +21xx3lnx-3xx3lnx+1/2lnx# = #5lnx +63lnx-9lnx+1/2lnx# = #lnx(5+63-9+1/2)# = #lnx(59+1/2)# = #119/2lnx# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1639 views around the world You can reuse this answer Creative Commons License