# Question #6856d

Mar 3, 2017

The volume of ${\text{Ca(OH)}}_{2}$ solution will be 8.33 mL.

#### Explanation:

The equation for the reaction is

$\text{2HCl + Ca(OH)"_2 → "CaCl"_2 + 2"H"_2"O}$.

1. Calculate the moles of $\text{HCl}$

$\text{Moles of HCl" = "0.025 00" color(red)(cancel(color(black)("L HCl"))) ×( "0.500 mol HCl")/(1 color(red)(cancel(color(black)("L HCl")))) = "0. 012 50 mol HCl}$

2. Calculate the moles of ${\text{Ca(OH)}}_{2}$

$\text{Moles of Ca(OH)"_2 = "0.012 50" color(red)(cancel(color(black)("mol HCl"))) × ("1 mol Ca(OH)"_2)/(2 color(red)(cancel(color(black)("mol HCl")))) = "0.006 250 mol Ca(OH)"_2}$

3. Calculate the molarity of the ${\text{Ca(OH)}}_{2}$

$\text{Volume of Ca(OH)"_2 = "0.006 250" color(red)(cancel(color(black)("mol Ca(OH)"_2))) × ("1 L Ca(OH)"_2)/(0.750 color(red)(cancel(color(black)("mol Ca(OH)"_2)))) = "0.008 33 L" = "8.33 mL}$