Question #a77c0

Question

Question #a77c0

1 Answer

Impact of this question

1447 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-28T12:00:13

Volume of water overflow is $219.92 c m^{3}$ $219.92cm^3$

Explanation:

Cylinder radius : $r_{c} = \frac{40}{2} = 20$ $r_c=40/2=20$ cm ; Cylinder height: $h_{c} = 70$ $h_c=70$ cm
Volume of cylinder : $V_{c} = π \cdot r_{c}^{2} \cdot h_{c} = π \cdot 20^{2} \cdot 70 \approx 87964.59 c m^{3}$ $V_c= pi*r_c^2*h_c= pi*20^2*70 ~~87964.59 cm^3$

Water cylinder radius : $r_{w} = \frac{40}{2} = 20$ $r_w=40/2=20$ cm ; water cylinder height: $h_{w} = 70 \cdot \frac{4}{5} = 56$ $h_w=70*4/5=56$ cm
Volume of water : $V_{w} = π \cdot r_{w}^{2} \cdot h_{w} = π \cdot 20^{2} \cdot 56 \approx 70371.68 c m^{3}$ $V_w= pi*r_w^2*h_w= pi*20^2*56 ~~70371.68 cm^3$

Cone radius : $r = 18$ $r=18$ cm ; cone height: $h = 70 \cdot \frac{3}{4} = 52.5$ $h=70*3/4 =52.5$ cm
Volume of cone : $V = \frac{1}{3} \cdot π \cdot r^{2} \cdot h = \frac{1}{3} \cdot π \cdot 18^{2} \cdot 52.5 \approx 17812.83 c m^{3}$ $V= 1/3*pi*r^2*h= 1/3*pi*18^2*52.5 ~~17812.83 cm^3$

Volume of water overflow $V - (V_{c} - V_{w}) = 17812.83 - (87964.59 - 70371.68) = 17812.83 - 17592.91 = 219.92 c m^{3}$ $V-(V_c -V_w) = 17812.83-(87964.59-70371.68) = 17812.83-17592.91= 219.92cm^3$

Science

Math

Humanities

... and beyond

Question #a77c0

1 Answer

Explanation:

Related questions

Impact of this question