Suppose, Event #D=#Pat picked a Diamond Card from pack, and,
Event #J=#pat picked a Jack from pack.
Then, Reqd. Prob.
#=P(DuuJ)=P(D)+P(J)-P(DnnJ)................(star).#
#(star1):P(D):-#
There are #52# cards in a pack, out of which #1# card can be
selected in #52# ways. Hence, the total no. #n# of outcomes is,
#n=52.#
There are #13# Diamond Cards in a pack, so, #1# such card can
be selected in #13# ways. Hence, the total no. #r# of outcomes
favorable to the occurance of the event #D# is, #r=13.#
#:. P(D)=r/n=13/52.....................(star1).#
#(star2): P(J):- "Similarly, "P(J)=4/52.................(star2).#
#(star3): P(DnnJ):-#
Event #DnnJ=#Card picked is a Jack of Diamond.
As discussed above, we have, #P(DnnJ)=1/52........(star3).#
Utilising #(star1), (star2) and (star3) in (star)#, we have,
#"The Reqd. Prob.="13/52+4/52-1/52=16/52=4/13.#
Enjoy Maths.!
