# Question #bc6e9

##### 1 Answer

(1). Amount of heat energy

#Q=msDeltaT#

where#s# is specific heat capacity of the material of sample.

For two blocks one of copper and other of iron, are of same mass, and are raised through same temperature. We see that amount of heat required is directly proportional to specific heat capacity.

#Qprops#

specific heat capacity of copper

specific heat capacity of iron

(2). Assuming that iron block in (1) above is immersed into

Let the final temperature of water be

Heat gained by water

Final temperature of iron block is also same.

Equating heat gained to heat lost we get

.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-

Alternatively

Let final temp of iron-water mixture be

Heat gained by water

Heat lost by iron block

Heat gained by water

Rise in temperature of water