# Question 529d1

Apr 8, 2017

change = |Δheight|/(time)

#### Explanation:

We want the ratio between the absolute value of the difference of the final and the initial elevation, divided by the amount of time they take to archive this chance.

It is similar to calculating the average speed of a car that started at meter $s = 2 m$ and ends at meter $s = 20 m$ in a total amount of time of $t = 10 \sec$. $s p e e d = \frac{| 20 - 2 | m}{10 s} = 1.8$m/s

The formula used here would be v = |Δs|/t

In your case: change = |Δheight|/(time)#

change = $\frac{139 - \left(- 21\right)}{8} = \frac{160}{8} = 20$m/h