# Question #fb6c4

Mar 9, 2017

The vertex is at $\left(- 5 , - 16\right)$

#### Explanation:

${x}^{2} + 10 x + 9$

$= {x}^{2} + 10 x + 25 + 9 - 25 \text{ } \pm {b}^{2} / 2$

$= {\left(x + 5\right)}^{2} - 16$

This is in the form ${\left(x + b\right)}^{2} + c$

The vertex is at $\left(- 5 , - 16\right)$