Question

Question #b415d

Answer 1

ops!....I read three....disregard my answer!

Explanation:

We can call our consecutive integers:
`n, n+1,n+2`
so we get:
`n+(n+1)+(n+2)=-66`
solve for `n`
`3n+3=-66`
`3n=-66-3`
`3n=-69`
`n=-69/3=-23`
so our integers will be:
`n=-23`
`n+1=-23+1=-22`
`n+2=-23+2=-21`

Answer 2

`-18,-17,-16,-15`

Explanation:

`"Let the 1st integer be "n`

Since they are consecutive then the next 3 integers will be.

`n+1,n+2,n+3`

`rArrn+(n+1)+(n+2)+(n+3)=-66`

simplifying left side gives.

`4n+6=-66`

subtract 6 from both sides.

`4ncancel(+6)cancel(-6)=-66-6`

`rArr4n=-72`

divide both sides by 4

`(cancel(4) n)/cancel(4)=(-72)/4`

`rArrn=-18`

`rArrn+1=-18+1=-17`

`rArrn+2=-18+2=-16`

`rArrn+3=-18+3=-15`

`"The 4 consecutive integers are "-15,-16,-17,-18`