# Question #a9c64

Mar 14, 2017

Your graph should look something like:

#### Explanation:

I am assuming that you meant $\frac{\textcolor{red}{3}}{\textcolor{b l u e}{5}}$ to be the slope.

Plot a point for the $y$ intercept of $- 9$ at $\left(0 , - 9\right)$

From the intercept point $\left(0 , - 9\right)$ move $\textcolor{b l u e}{5}$ units to the right (in the positive $x$ direction) then up $\textcolor{red}{3}$ units (in the positive $y$ direction); that should put you at $\left(5 , - 6\right)$; plot a second point at this location.

To help verify your results, repeat this process: right $\textcolor{b l u e}{5}$ and up $\textcolor{red}{3}$ to give a third point at $\left(10 , - 3\right)$

Draw a straight line through the points you have plotted to obtain the required graph.