Question #a9c64

1 Answer
Mar 14, 2017

Answer:

Your graph should look something like:
enter image source here

Explanation:

I am assuming that you meant #color(red)3/color(blue)5# to be the slope.

Plot a point for the #y# intercept of #-9# at #(0,-9)#

From the intercept point #(0,-9)# move #color(blue)5# units to the right (in the positive #x# direction) then up #color(red)3# units (in the positive #y# direction); that should put you at #(5,-6)#; plot a second point at this location.

To help verify your results, repeat this process: right #color(blue)5# and up #color(red)3# to give a third point at #(10,-3)#

Draw a straight line through the points you have plotted to obtain the required graph.