If #BE#||#CD#, find #x#?

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Answer 1 · 2017-03-13T11:59:04

#x=10#

As #BE#||#CD#, #DeltaABE# and #DeltaACD# are similar.

Hence, #(AB)/(BC)=(AE)/(ED)#

i.e. #25/15=(7x-40)/(18)#

or #15xx(7x-40)=25xx18#

or #105x-600=450#

i.e. #105x=450+600=1050#

and #x=1050/105=10#

Answer 2 · 2017-03-13T12:06:18

#x=10.#

Lines #BE, and CD# are Parallel, and, #AC and AD# are

transverses. Therefore, by Geometry, we know that,

#(AB)/(BC)=(AE)/(ED) rArr 25/15=(7x-40)/18.#

#rArr 7x-40=25/15*18=30 rArr 7x=30+40.#

#:. x=70/7=10.#

Enjoy Maths.!