# Question #62fa4

May 28, 2017

$- 1 \pm \frac{\sqrt{10}}{2}$

#### Explanation:

y = -2x^2 - 4x + 3 = 0
Since D = b^2 - 4ac = 16 + 24 = 40 is not a perfect square, then we can't use the factoring method.
In this case, the best way is using the improved quadratic formula (Socratic Search).
$D = {d}^{2} = {b}^{2} - 4 a c = 40$ --> $d = \pm 2 \sqrt{10}$
There are 2 real roots:
$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = \frac{4}{-} 4 \pm \frac{2 \sqrt{10}}{-} 4 = - 1 \pm \frac{\sqrt{10}}{2}$