# Question #a3859

Mar 17, 2017

${T}_{2} = \text{846 K}$ or ${573}^{\circ} \text{C}$

#### Explanation:

From the Ideal Gas Laws we know that ${\left(\frac{P V}{T}\right)}_{1} = {\left(\frac{P V}{T}\right)}_{2}$

At constant pressure this is just ${\left(\frac{V}{T}\right)}_{1} = {\left(\frac{V}{T}\right)}_{2}$
Inserting our given values into this equation with the correct temperature values we get:

$\frac{\text{0.300 L"/"423 K" = "0.600 L}}{T} _ 2$ ; ${T}_{2} = \frac{0.600}{\frac{0.300}{\text{423 K}}}$

${T}_{2} = \text{846 K}$ or ${573}^{\circ} \text{C}$