Question #a2443

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Question #a2443

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Answer 1 · 2017-03-19T14:29:11

Ratio of surface area to volume of a cylinder of radius $r = 4$ $r=4$ inch and height $h = 6$ $h=6$ inch is given by

$\frac{Total Surface Area}{Volume} = \frac{2 π r^{2} + 2 π r h}{π r^{2} h}$ $"Total Surface Area"/"Volume"=(2pir^2+2pirh)/(pir^2h)$

$= \frac{2 π r^{2}}{π r^{2} h} + \frac{2 π r h}{π r^{2} h} = \frac{2}{h} + \frac{2}{r} = \frac{2}{6} + \frac{2}{4} = \frac{1}{3} + \frac{1}{2} = \frac{5}{6}$ $=(2pir^2)/(pir^2h)+(2pirh)/(pir^2h)=2/h+2/r=2/6+2/4=1/3+1/2=5/6$

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