Question #4c8a8
1 Answer
Mar 18, 2017
Explanation:
We have the following equations.
#xcolor(red)(+y)=10to(1)#
#color(red)(y)=4xto(2)# Solve using the
#color(blue)"substitution method"# That is substitute
#color(red)(y)=4x" into " (1)#
#rArrx+4x=10#
#rArr5x=10# divide both sides of the equation by 5
#(cancel(5) x)/cancel(5)=10/5#
#rArrx=2# Substitute this value into ( 2 ) to obtain value for y
#rArry=4xx2=8#
#color(blue)"As a check"# Substitute these values into the original statements and if they are true then these are the solutions.
#x+y=2+8=10to" True"#
#y=4xx2=8to" True"#
#rArrx=2" and "y=8" are the solution"#