Question

Question #508e0

Answer 1

`lim_(xrarr0) (sin^2 5x)/(5x^2) = 5`

Explanation:

`lim_(xrarr0) (sin^2 5x)/(5x^2) = lim_(xrarr0) (sin 5x)^2/((5x)x)`

`= lim_(xrarr0) 5(sin 5x)^2/((5x)(5x))`

`= 5 lim_(xrarr0) (sin 5x)/(5x) (sin5x)/(5x)`

`= 5(1)(1) = 5`