Question

Question #5fc94

Answer 1

The frictional force is 9.8 N.

Explanation:

I will assume 1) this mass is on a horizontal surface and 2) the 70 N force is applied horizontally.

The formula for the frictional force, `F_f`, is

`F_f = mu*N`

where `mu` is the coefficient of friction and N is Normal force. Normal force means the force pressing the object to the surface it is sliding on. In this case, it is the weight of the mass, so `N = m*g`.

`F_f = 0.02*50 kg*9.8 m/s^2 = 9.8 N`

The net force will be
`70 N - 9.8 N = 60.2 N`
The friction will not be large enough to prevent the mass from sliding, so the mass will accelerate.

I hope this helps,
Steve