Question #e4692

1 Answer
May 29, 2017

Answer:

2.675 grams of Helium.

Explanation:

995 torr equals 1.309 atm (P).
T is #173.15+25 = 298.15# K
Now we can use this formula (The ideal gas law)

#P*V = n*R*T#

#1.309*12.5 = n*0.082056*298.15#

#n = 0.6688# moles of Helium.

Since Helium has a mass of 4 g/mol, you can compute

#Mass = 0.6688*4#

#Mass = 2.675# grams of Helium.