Question #d9f07

2 Answers
Mar 20, 2017

Answer:

#NaOH (aq) + CO_2 (g) -> NaHCO_3#

Explanation:

The reaction depends on the concentration of the alkali solution #NaOH#).

When #NaOH# is concentrated, pH > 10, the reaction produces sodium hydrogen carbonate (#NaHCO_3)#:

#NaOH (aq) + CO_2 (g) -> NaHCO_3#

Mar 20, 2017

Answer:

#OH^-)(aq) + CO_2(g) = HCO_3^-)(aq)#

#CO_2(aq) + 2OH^-)(aq) = CO_3^(2-)(aq) + H_2O(l)#

Explanation:

When pH is very high or of a very basic nature

= #NaOH + CO_2 = NaHCO_3 #

The ionic reaction is

First write the ions formed

# Na^+(aq) + OH^-)(aq) + CO_2(g) = Na^+(aq) + HCO_3^-)(aq)#

Where g = gaseous
aq = aqueous

Cut out the same ions

#cancel(Na^+(aq)) + OH^-)(aq) + CO_2(g) = cancel(Na^+(aq)) + HCO_3^-)(aq)#

= #OH^-)(aq) + CO_2(g) = HCO_3^-)(aq)#

This is how we write ionic reactions

Another reaction can be also formed when pH is low or when its more acidic is of a good strength is

#2NaOH + CO_2 = Na_2CO_3 + H_2O#

#2Na^+(aq) +2OH^-)+ CO_2(aq) = 2Na^+(aq) + CO_3^(2-)(aq) + H_2O(l)#

Cut out the same ions

#cancel(2Na^+(aq)) + 2OH^-)(aq) + CO_2(aq) = cancel(2Na^+(aq)) + CO_3^(2-)(aq) + H_2O(l)#

#CO_2(aq) + 2OH^-)(aq) = CO_3^(2-)(aq) + H_2O(l)#