Question

Prove that `(sin2x-cos2x)/(sinxcosx)=-cot2x`?

Answer 1

`(sin^2x-cos^2x)/(sinx cosx)=-cot2x`

Explanation:

I presume you mean

`(sin^2x-cos^2x)/(sinx cosx)`

and this can be written as

`-(cos^2x-sin^2x)/(2sinx cosx)xx2`

= `-(cos2x)/(sin2x)xx2`

= `-2cot2x`