# Question #0a25a

Mar 20, 2017

Lithium hydroxide has a mass of 24 g per mole, so 2.50 g is 0.104 mole.

Dissolve this in 1.50 L, and the concentration is

$\left[L i O H\right] = 0.104 m o l \div 1.50 L = 0.0694 \frac{\text{mol}}{L}$

Since LiOH is a strong base, it ionizes completely

$L i O H \rightarrow L {i}^{+} + O {H}^{-}$

Since each one mole of LiOH produces one mole of $O {H}^{-}$, the concentration of $O {H}^{-}$ will be $0.0694$ mol/L as well.