# Question b579a

Mar 27, 2017

$4627 J$ or $4.6 k J$

#### Explanation:

Recognize the equation to use

$q = m \cdot c \cdot \Delta T$

We know the mass($m$)- $66.7 g$

We know the specific heat capacity($c$)-0.75J/(g˚C)

We can find $\Delta T$ from

$\Delta T = {T}_{2} - {T}_{1} = 92.5 - 0$

DeltaT=92.5˚C

:.q= 66.7cancelg*0.75J/cancel(g˚C)*92.5cancel(˚C)#

$\Rightarrow q = 4627 J \mathmr{and} 4.6 k J$

To get $k J$, simply multiply by ${10}^{-} 3$ or divide by $1000$

This is how

$4627 \cancel{J} \cdot \frac{1 k J}{1000 \cancel{J}}$

$O R$

$4627 \cdot {10}^{-} 3 k J$