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Answer 1 · 2017-03-21T17:36:14

Length 11 miles and width 6 miles

If the width is taken to be x miles, its length would be x+6 and area would be x(x+6). Thus,

x(x+6)=55.

This can be solved for x by factorising the quadratic expression #x^2+6x-55=0#

(x+11)(x-5)=0. this gives x=5 or -11. Since x cannot have a negative value, it would be x=5

Width is 5 miles hence length would be 6more that is 11 miles.

Answer 2 · 2017-03-21T17:53:04

Length#=11#miles,width#=5#miles

Let the length be # x#

then the width will be #x-6#

#x(x-6)=55#

#x^2-6x=55#

#x^2-6x-55=0#

#(x+5)(x-11)=0#

#x=-5# or #x=11#

substitute #x=11#

#11-6=5# miles#=width#

Length#=11#miles