Put #y-2=-2/3(x+1)# into standard form?

1 Answer

#2x+3y=4#

Explanation:

We have:

#y-2=-2/3(x+1)#

and we want to put it into a form that looks like:

#ax+by=c; a, b, c in ZZ# - or in other words, no fractions.

We can do this by first multiplying both sides by 3 to get rid of the denominator on the right side:

#3(y-2)=-2(x+1)#

Distribute out the brackets:

#3y-6=-2x-2#

Let's now move the #x# term to the left hand side and the constants to the right:

#2x+3y=4#

Let's check this by graphing both forms. This is #y-2=-2/3(x+1)#:

graph{y-2=-2/3(x+1) [-10, 10, -5, 5]}

and this is #2x+3y=4#:

graph{2x+3y-4=0 [-10, 10, -5, 5]}