Question #4e523
1 Answer
Mar 25, 2017
Explanation:
Consider the term
#e^(-3lnx)#
#" Now " color(red)(bar(ul(|color(white)(2/2)color(black)(e^(ln(f(x))=f(x))color(white)(2/2)|))))larr" inverse functions" #
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(logx^nhArrnlogx)color(white)(2/2)|)))#
#rArre^(-3lnx)=e^(lnx^-3)=x^-3#
#rArry=x^5e^(-3lnx)=x^5xxx^-3=x^2#
#rArrdy/dx=2x#
