# Question #28e8a

Mar 26, 2017

The escape velocity is the one giving enough kinetic energy to balance gravitational energy exactly, so its total energy is zero
$\frac{1}{2} m {v}^{2} = G M \frac{m}{r}$

#### Explanation:

$v = \sqrt{2 G \frac{M}{r}}$
$v = \sqrt{2 \left(6.67 \times {10}^{-} 11\right) \frac{5.1 \times {10}^{24}}{57.0 \times {10}^{5}}} = 1.09 \times {10}^{4} \frac{m}{s}$