# What is [H_3O^+] for a solution whose pH-=2.85?

Mar 26, 2017

Well, first we had better specify what $p H$ is..........

#### Explanation:

And I assume that $2.85 = - {\log}_{10} \left[{H}^{+}\right]$

And taking antilogs..........

${10}^{- 2.85} = \left[{H}^{+}\right]$

So $\left[{H}^{+}\right] = 1.41 \times {10}^{-} 3 \cdot m o l \cdot {L}^{-} 1. \ldots \ldots \ldots \ldots$

See here for an example...........