What is the concentration of a #10*cm^3# volume of a #H_2O_4# at #9.8*mol*dm^-3# concentration that is diluted to a #100*cm^3# volume?

1 Answer
Mar 27, 2017

Answer:

#"Concentration"="Moles of solute"/"Volume of solution"#

Explanation:

And given #"Concentration"="Moles of solute"/"Volume of solution"#, #"concentration"# has units of #mol*L^-1#, or #mol*dm^-3#.

Here we have (I think):

#(10*cm^3xx10^-3*dm^3*cm^-3xx9.8*mol*dm^-3)/(1000*cm^3xx10^-3*dm^3*cm^-3)#

#=0.098*mol*L^-1# or #0.098*mol*dm^-3#, with respect to #H_2SO_4(aq)#.

This makes sense without all the pesky conversion factors, because you are diluting the original solution by a hundredfold.