Question

What is the concentration of a `10*cm^3` volume of a `H_2O_4` at `9.8*mol*dm^-3` concentration that is diluted to a `100*cm^3` volume?

Answer 1

`"Concentration"="Moles of solute"/"Volume of solution"`

Explanation:

And given `"Concentration"="Moles of solute"/"Volume of solution"`, `"concentration"` has units of `mol*L^-1`, or `mol*dm^-3`.

Here we have (I think):

`(10*cm^3xx10^-3*dm^3*cm^-3xx9.8*mol*dm^-3)/(1000*cm^3xx10^-3*dm^3*cm^-3)`

`=0.098*mol*L^-1` or `0.098*mol*dm^-3`, with respect to `H_2SO_4(aq)`.

This makes sense without all the pesky conversion factors, because you are diluting the original solution by a hundredfold.