How many ions result from the dissolution of a #11.1*g# mass of calcium chloride in water?

1 Answer
Mar 27, 2017

Answer:

Approx. #1.81xx10^23# ions

Explanation:

#"Moles of calcium chloride"# #=# #(11.1*g)/(110.98*g*mol^-1)=0.100*mol#

And thus in solution:

#CaCl_2(s) + "excess "H_2OrarrCa^(2+) + 2Cl^(-)#, there are #0.100*mol# #Ca^(2+)# ions, and #0.200*mol# #Cl^(-)# ions, i.e. #0.300*mol# of ions...........

And #0.300*molxxN_A=0.300*molxx6.022xx10^23*mol^-1#

#1.81xx10^23# ions..........