# Question #baf96

Mar 28, 2017

$8.00 \cdot g$ of what? Sodium hydroxide?

#### Explanation:

We can guess that you mean $\text{1 US gallon} \equiv 3.785 \cdot L$. We cannot guess the solute. Would you review this question?

If the solute is sodium hydroxide, then,

$\left[N a O H\right] = \text{Moles of NaOH"/"Volume}$

$= \frac{\frac{8.00 \cdot g}{40.00 \cdot g \cdot m o {l}^{-} 1}}{1.0 \cdot {\text{gallons"xx3.785*L*"gallon}}^{-} 1}$

$5.28 \times {10}^{-} 2 \cdot m o l \cdot {L}^{-} 1$ with respect to $N a O H$.

So $\left[N {a}^{+}\right] = \left[H {O}^{-}\right] = 5.28 \times {10}^{-} 2 \cdot m o l \cdot {L}^{-} 1$.

What is the $p H$ of this solution?