# Question #f867b

$\vec{\mathrm{dB}} = {\mu}_{0} / \left(4 \pi\right) \frac{I \vec{\mathrm{dl}} X \vec{R}}{R} ^ 3$
This gives magnetic induction for a conducting vector element $\vec{\mathrm{dl}}$ carrying current $I$ at a distance $\vec{R}$ from $\vec{\mathrm{dl}}$.
This shows how the magnetic field $\vec{\mathrm{dB}}$ is proportional to the current $I$.