Question #de3c1

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Answer 1 · 2017-03-29T06:49:12

$~~63750$ $m^3$

For the volume, we need the radius

As we know, that the diameter is twice the radius, the radius would be $50/2=25$ $m$

Let's find the volume

$color(blue)("Volume"=4/3 pi r^3$

$rarr4/3 *3.14*25^3$

$rarr4/3*3.14*25*25*25$

$rarr4/3*3.14*15625$

$rarr1.3*3.14*15625$

$rarr4.08*15625$

$color(green)(rArr63750$ $color(green)(m^3$

So, the volume of the spaceship is approximately $63750$ $m^3$

Hope this helps..! :)