Question

Question #de3c1

Answer 1

`~~63750` `m^3`

Explanation:

For the volume, we need the radius

As we know, that the diameter is twice the radius, the radius would be `50/2=25` `m`

Let's find the volume

`color(blue)("Volume"=4/3 pi r^3`

`rarr4/3 *3.14*25^3`

`rarr4/3*3.14*25*25*25`

`rarr4/3*3.14*15625`

`rarr1.3*3.14*15625`

`rarr4.08*15625`

`color(green)(rArr63750` `color(green)(m^3`

So, the volume of the spaceship is approximately `63750` `m^3`

Hope this helps..! :)