Question #de3c1

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Answer 1 · 2017-03-29T06:49:12

$\approx 63750$ $~~63750$ $m^{3}$ $m^3$

For the volume, we need the radius

As we know, that the diameter is twice the radius, the radius would be $\frac{50}{2} = 25$ $50/2=25$ $m$ $m$

Let's find the volume

$Volume = \frac{4}{3} π r^{3}$ $color(blue)("Volume"=4/3 pi r^3$

$\to \frac{4}{3} \cdot 3.14 \cdot 25^{3}$ $rarr4/3 *3.14*25^3$

$\to \frac{4}{3} \cdot 3.14 \cdot 25 \cdot 25 \cdot 25$ $rarr4/3*3.14*25*25*25$

$\to \frac{4}{3} \cdot 3.14 \cdot 15625$ $rarr4/3*3.14*15625$

$\to 1.3 \cdot 3.14 \cdot 15625$ $rarr1.3*3.14*15625$

$\to 4.08 \cdot 15625$ $rarr4.08*15625$

$\Rightarrow 63750$ $color(green)(rArr63750$ $m^{3}$ $color(green)(m^3$

So, the volume of the spaceship is approximately $63750$ $63750$ $m^{3}$ $m^3$

Hope this helps..! :)