Mar 29, 2017

A 0.10 mol/L aqueous solution of sodium nitrate has a pH of 7.00.

#### Explanation:

Sodium nitrate is the salt formed by the reaction of nitric acid with sodium hydroxide.

The equation for the reaction is

$\text{HNO"_3 + "KOH" → "KNO"_3 + "H"_2"O}$

In ionic form, the equation is

$\text{H"^"+" + "OH"^"-" → "H"_2"O}$

${\text{HNO}}_{3}$ is a very strong acid, so its conjugate base $\text{NO"_3^"-}$ is a very weak base.

It has no tendency to act as a base in aqueous solution.

In the same way, the conjugate acid of the strong base $\text{KOH}$ is $\text{K"^"+}$.

$\text{K"^"+}$ has no tendency to act as a base in aqueous solution.

∴ The pH of a neutral solution is 7.00.