# Question #74b68

##### 1 Answer

#### Answer:

Either factor or use quadratic formula. In this case, the zeros are

#### Explanation:

Solving a quadratic function means to find the roots/zeros (same meaning, different word).

There are two ways to accomplish this:

- Factor the equation (from standard to factored form).
- Use the quadratic formula (in standard form).

Let's try factoring. Factoring is the fast and easier method of solving a quadratic function.

So first, let's find a common factor. In this case, I noticed that

#f(x)=-8x^2+8x+48#

#f(x)=-8(x^2-x-6)#

I took out the negative sign to make factoring much easier.

Now, we have a simple trinomial. So let's factor it normally: what two numbers added equals

#f(x)=-8(x-3)(x+2)#

And those are the zeros:

If factoring did **not** work, we would have to use the quadratic formula and plug in the numbers from standard form.

Hope this helps :)