Question #74b68

1 Answer
Mar 30, 2017

Answer:

Either factor or use quadratic formula. In this case, the zeros are #3# and #-2#.

Explanation:

Solving a quadratic function means to find the roots/zeros (same meaning, different word).

There are two ways to accomplish this:

  1. Factor the equation (from standard to factored form).
  2. Use the quadratic formula (in standard form).

Let's try factoring. Factoring is the fast and easier method of solving a quadratic function.

So first, let's find a common factor. In this case, I noticed that #8# is common in all terms. So let's use that as our greatest common factor.

#f(x)=-8x^2+8x+48#

#f(x)=-8(x^2-x-6)#

I took out the negative sign to make factoring much easier.

Now, we have a simple trinomial. So let's factor it normally: what two numbers added equals #b# and multiplied, equals #ac#? In this case, it is #-3# and #2#.

#f(x)=-8(x-3)(x+2)#

And those are the zeros: #3# and #-2#.

If factoring did not work, we would have to use the quadratic formula and plug in the numbers from standard form.

Hope this helps :)