Question

A bag has 6 green marbles, 2 blue marbles, and 8 white marbles. If we draw one at a time, and then replace the marbles, what is the probability of a. getting a green one and then a blue? b. Of getting a white and then another white?

Answer 1

`P(green, blue)=3/64, P(white, white)=1/4`

Explanation:

Probability of green then blue

With replacement, on our first draw, the probability of getting a green marble is `6/16=3/8`

and then getting a blue marble is `2/16=1/8`.

We multiply the probabilities to get `3/8xx1/8=3/64`

Probability of white then white

We go through the same process as above. The first draw gives us `8/16=1/2` and the second draw gives us the same, so we multiply `1/2xx1/2=1/4`