The volume is
The integral using the method of disks is
From the figure I am assuming that the problem is rotating
Using the shell method our radius will be some value of
The shell height is just the function
So the integral using the shell method is
We can evaluate this integral using integration by parts.
The parts formula is
Proceeding we have
Now onward with the disk method.
We have to get things in terms of
We will integrate over the interval
Our radius is
Using the method of disks the integral for the volume is