Question #5c77f

1 Answer
Apr 4, 2017

Answer:

Option (5)

Explanation:

Formula to get the resolved part of a vector #vecV# along the direction making an angle #theta# with it is given by

#vecV_"resolved part"=vecVcostheta#

#vecA# makes an angle #theta=0^@# with the X-axis and it makes an angle #theta=90^@# with the Y-axis.

So its resolved part along X-axis

#vecA_x=vecAcos0^@#

And its resolved part along Y-axis

#vecA_y=vecAcos90^@#

Again #vecB# makes an angle #theta=(180^@-60^@)# with the X-axis and it makes an angle #theta=30^@# with the Y-axis.

So its resolved part along X-axis

#vecB_x=vecBcos(180^@-60^@)=-Bcos60^@#

And its resolved part along Y-axis

#vecB_y=vecBcos30^@#