Question #593b2

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Answer 1 · 2017-04-08T10:10:13

frequency = #4.5692729xx10^14 s^-1#

Energy must be absorbed during the transition from n2 to n3 in the hydrogen atom.

#DeltaE = (-R) [1/"n(final)" - 1/"n(initial)"]#

Where R is the Ryderberg's constant in joules = #2.179872172xx10^(-18)J#

n final is the final energy state and n initial is energy state which we started from

#Delta E =( -2.179872172xx10^(-18)J)[1/(3^2) - 1/(2^2)]#

#Delta E = ( -2.179872172xx10^(-18)J)[-0.138888888889]#

#Delta E = 3.0276002xx10^-19J#

This makes sense as the #Delta E# is positive means absorbing energy

frequency = #(DeltaE)/h#

Where h is Planck's constant which is equal to #6.626 * 10^(-34)J*s#

= #(3.0276002xx10^-19J)/(6.626 * 10^(-34)J*s)= 4.5692729xx10^14#

frequency = #4.5692729xx10^14 s^-1#