Question #bbc12

Question

1539 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-04T21:44:12

See long answer below.

This involves finding the volume of the big and small boxes and subtracting them.

The volume of the small box

$V = L \times W \times H$ $V = L xx W xx H$

$V = 12 \cdot 8 \cdot 4$ $V = 12*8*4$

$V = {384 in}^{2}$ $V = "384 in"^2$

The volume of the big box

$V = L \times W \times H$ $V = L xx W xx H$

$V = 20 \cdot 15 \cdot 9$ $V = 20 * 15 * 9$

$V = {2700 In}^{2}$ $V = "2700 In"^2$

So

$2700 - 384 = 2316$ $2700-384 = 2316$

Therefore, the space left is ${2316 in}^{2}$ $"2316 in"^2$ .