What is (1+i)^6 ?
1 Answer
Oct 14, 2017
Explanation:
(1+i)^2 = 1+2i+i^2 = 2i
(2i)^3 = 2^3*i^2*i = -8i
So:
(1+i)^6 = ((1+i)^2)^3 = -8i
(1+i)^2 = 1+2i+i^2 = 2i
(2i)^3 = 2^3*i^2*i = -8i
So:
(1+i)^6 = ((1+i)^2)^3 = -8i