What mass of sodium chloride is required in the following scenario?

A #350.00*L# volume of #NaCl(aq)# is required at #4.315*mol*L^-1# concentration. What mass of solute is required?

1 Answer
Apr 6, 2017

Answer:

You would need over #88*kg# of salt........

Explanation:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#.

And thus #"moles of solute"="concentration"xx"volume of solution"#

And the problem gives us 2 of these 3 quantities, we just have to multiply and divide.

#"moles of solute"=350.00*cancelLxx4.315*mol*cancel(L^-1)=1510.25*mol#.

And we then need to multiply this molar quantity by the molar mass of #NaCl# in #g*mol^-1#:

#1510.25*cancel(mol)xx(35.45+22.99)*g*cancel(mol^-1)=#

#??*g# of salt..........