# If there is a 5*mol quantity of N_2, how much dihydrogen is required to make ammonia?

Apr 6, 2017

#### Answer:

To make ammonia, $N {H}_{3}$?

#### Explanation:

We assess the stoichiometric reaction:

${N}_{2} \left(g\right) + 3 {H}_{2} \left(g\right) \rightarrow 2 N {H}_{3} \left(g\right)$

And thus, if we have a $5$ $m o l$ quantity of dinitrogen, the reaction stoichiometry INSISTS that we must have a $15$ $m o l$ quantity of dihydrogen gas. Are you satisfied?