Question

If there is a `5*mol` quantity of `N_2`, how much dihydrogen is required to make ammonia?

Answer 1

To make ammonia, `NH_3`?

Explanation:

We assess the stoichiometric reaction:

`N_2(g) + 3H_2(g) rarr 2NH_3(g)`

And thus, if we have a `5` `mol` quantity of dinitrogen, the reaction stoichiometry INSISTS that we must have a `15` `mol` quantity of dihydrogen gas. Are you satisfied?