How do we represent stoichiometric reaction between strontium chloride, and sodium phosphate?

1 Answer
Sep 9, 2017

Answer:

You use the molar ratio from the balanced equation.

Explanation:

Your balanced equation might look something like this:

#"3SrCl"_2·6"H"_2"O" + "2Na"_3"PO"_4 → "Sr"_3("PO"_4)_2 + "6NaCl" + 6"H"_2"O"#

The important thing is that atoms of #"Sr"# must be balanced.

The molar ratio is then either #("1 mol Sr"_3("PO"_4)_2)/("3 mol SrCl"_2·6"H"_2"O")# or #("3 mol SrCl"_2·6"H"_2"O")/("1 mol Sr"_3("PO"_4)_2)#

For example, to convert 1.20 mol of #"SrCl"_2·6"H"_2"O"# to moles of #"Sr"_3("PO"_4)_2 "#, you would write

#"1.20 mol SrCl"_2·6"H"_2"O" × ("1 mol Sr"_3("PO"_4)_2)/("3 mol SrCl"_2·6"H"_2"O") = "0.400 mol Sr"_3("PO"_4)_2#